Eureka Math Grade 5 Module 2 Lesson 3 Answer Key (2024)

Engage NY Eureka Math 5th Grade Module 2 Lesson 3 Answer Key

Eureka Math Grade 5 Module 2 Lesson 3 Problem Set Answer Key

Question 1.
Draw a model. Then, write the numerical expressions.
a. The sum of 8 and 7, doubled

Answer:
The sum of 8 and 7, doubled = 30.

Explanation:
In the above-given question,
given that,
the sum of 8 and 7 is 15.
8 + 7 = 15.
15 + 15 = 30.
Eureka Math Grade 5 Module 2 Lesson 3 Answer Key (1)

b. 4 times the sum of 14 and 26

Answer:
The sum of 14 and 26, 4 times = 160.

Explanation:
In the above-given question,
given that,
the sum of 14 and 26 is 40.
40 + 40 + 40 + 40 = 160.
14 + 26 = 40.
Eureka Math Grade 5 Module 2 Lesson 3 Answer Key (2)

c. 3 times the difference between 37.5 and 24.5

Answer:
The difference of 37.5 and 24.5, 3 times = 13.0.

Explanation:
In the above-given question,
given that,
the difference of 37.5 and 24.5 is 13.0.
37.5 – 24.5 = 13.0.
13.0 + 13.0 + 13.0 = 39.
Eureka Math Grade 5 Module 2 Lesson 3 Answer Key (3)

d. The sum of 3 sixteens and 2 nines

Answer:
The sum of 3 sixteens and 2 nines = 30.

Explanation:
In the above-given question,
given that,
the sum of 3 sixteens and 2 nines is 66.
48 + 18 = 66.
16 + 16 + 16 + 9 + 9 = 66.
Eureka Math Grade 5 Module 2 Lesson 3 Answer Key (4)

e. The difference between 4 twenty-fives and 3 twenty-fives

Answer:
The difference between 4 25 and 3 25 = 25.

Explanation:
In the above-given question,
given that,
the difference between 4 25 and 3 25 = 25.
100 – 75 = 25.
4 x 25 = 100.
3 x 25 = 75.
100 – 75 = 25.
Eureka Math Grade 5 Module 2 Lesson 3 Answer Key (5)

f. Triple the sum of 33 and 27

Answer:
The sum of 33 and 27, 3 times = 180.

Explanation:
In the above-given question,
given that,
the sum of 33 and 27 is 180.
60 + 60 + 60 = 180.
33 + 27 = 60.
Eureka Math Grade 5 Module 2 Lesson 3 Answer Key (6)

Question 2.
Write the numerical expressions in words. Then, solve.

Expression

Words

The Value of the Expression

a. 12×(5+25)12 times the sum of 5 and 2512 x ( 30) = 360
b. (62–12)×1111 times the difference of 62 and 12(50) x 11 = 550
c. (45+55)×2323 times the sum of 45 and 55(100) x 23 = 2300
d. (30×2)+(8×2)product of 30,2 and product of 8,2(60) + (16) = 76

Answer:
360.

Explanation:
In the above-given question,
given that,
12 x ( 5 + 25).
12 x (30).
360.

Answer:
550.

Explanation:
In the above-given question,
given that,
(62 – 12) × 11
50 x 11 = 550.

Answer:
2300.

Explanation:
In the above-given question,
given that,
(45 + 55) × 23.
100 x 23.
2300.

Answer:
76.

Explanation:
In the above-given question,
given that,
(30×2)+(8×2)
60 + 16.
76.

Question 3.
Compare the two expressions using > , < , or = . In the space beneath each pair of expressions, explain how you can compare without calculating. Draw a model if it helps you.
Eureka Math Grade 5 Module 2 Lesson 3 Answer Key (7)

Answer:
600 > 360.

Explanation:
In the above-given question,
given that,
24 x (20 + 5).
24 x 25.
600.
(20 + 5) x 12.
30 x 12.
360.
600 > 360.

Answer:
487 > 513.

Explanation:
In the above-given question,
given that,
18 x 27.
487.
20 twenty-seven – 1 27.
540 – 27.
513.
487 < 513.

Answer:
171 = 171.

Explanation:
In the above-given question,
given that,
19 x 9.
171.
3 nineteens tripled.
57 x 3.
171.
171 = 171.
Eureka Math Grade 5 Module 2 Lesson 3 Answer Key (8)

Question 4.
Mr. Huynh wrote the sum of 7 fifteens and 38 fifteens on the board.
Draw a model, and write the correct expression.

Answer:
The sum of 7 fifteens and 38 fifteens = 675.

Explanation:
In the above-given question,
given that,
the sum of 7 fifteens and 38 fifteens
105 + 570 = 675.
Eureka Math Grade 5 Module 2 Lesson 3 Answer Key (9)

Question 5.
Two students wrote the following numerical expressions.
Angeline: (7 + 15) × (38 + 15)
MeiLing: 15 × (7 + 38)
Are the students’ expressions equivalent to your answer in Problem 4? Explain your answer.

Answer:
Yes, the student’s expressions equivalent.

Explanation:
In the above-given question,
given that,
Angeline: (7 + 15) × (38 + 15)
Meiling: 15 × (7 + 38)
105 + 570 = 675.

Question 6.
A box contains 24 oranges. Mr. Lee ordered 8 boxes for his store and 12 boxes for his restaurant.
a. Write an expression to show how to find the total number of oranges ordered.

Answer:
The total number of oranges ordered= 480.

Explanation:
In the above-given question,
given that,
A box contains 24 oranges. Mr. Lee ordered 8 boxes for his store and 12 boxes for his restaurant.
( 24 x 8 ) + ( 24 x 12)
192 + 288
480

b. Next week, Mr. Lee will double the number of boxes he orders. Write a new expression to represent the number of oranges in next week’s order.

Answer:
The total number of oranges ordered= 960.

Explanation:
In the above-given question,
given that,
A box contains 24 oranges. Mr. Lee ordered 8 boxes for his store and 12 boxes for his restaurant.
( 24 x 8 ) + ( 24 x 12)
192 + 288
480 + 480 = 960

c. Evaluate your expression from Part (b) to find the total number of oranges ordered in both weeks.

Answer:
The total number of oranges ordered in both weeks = 1440.

Explanation:
In the above-given question,
given that,
960 + 480 = 1440.

Eureka Math Grade 5 Module 2 Lesson 3 Exit Ticket Answer Key

Question 1.
Draw a model. Then, write the numerical expressions.
a. The difference between 8 forty-sevens and 7 forty-sevens

Answer:
The difference of 8 forty-sevens and 7 forty-sevens = 47.

Explanation:
In the above-given question,
given that,
the difference of 8 forty sevens and 7 forty-sevens.
8 x 47 – 7 x 47.
376 – 329.
47

b. 6 times the sum of 12 and 8

Answer:
The sum of 12 and 8, 6 times = 120.

Explanation:
In the above-given question,
given that,
the sum of 12 and 8 is 120.
20 + 20 + 20 + 20 + 20 + 20 = 120.
12 + 8 = 20.

Question 2.
Compare the two expressions using >, <, or =.
Eureka Math Grade 5 Module 2 Lesson 3 Answer Key (10)

Answer:
4836 > 2028.

Explanation:
In the above-given question,
given that,
62 x ( 70 + 8).
62 x 78 = 4836.
(70 + 8) x 26.
78 x 26 = 2,028.
Eureka Math Grade 5 Module 2 Lesson 3 Answer Key (11)

Eureka Math Grade 5 Module 2 Lesson 3 Homework Answer Key

Question 1.
Draw a model. Then, write the numerical expressions.
a. The sum of 21 and 4, doubled
b. 5 times the sum of 7 and 23
c. 2 times the difference between 49.5 and 37.5
d. The sum of 3 fifteens and 4 twos
e. The difference between 9 thirty-sevens and 8 thirty-sevens
f. Triple the sum of 45 and 55

Answer:
The sum of 21 and 4, 2 times = 50.

Explanation:
In the above-given question,
given that,
the sum of 21 and 4 is 25.
25 + 25 = 50.
21 + 4 = 25.
Eureka Math Grade 5 Module 2 Lesson 3 Answer Key (12)

Answer:
The sum of 7 and 23, 5 times = 150.

Explanation:
In the above-given question,
given that,
the sum of 7 and 23 is 30.
30 + 30 + 30 + 30 + 30 = 150.
7 + 23 = 30.
Eureka Math Grade 5 Module 2 Lesson 3 Answer Key (13)

Answer:
2 times the difference between 49.5 and 37.5= 24.

Explanation:
In the above-given question,
given that,
2 times the difference between 49.5 and 37.5
49.5 – 37.5 = 12.0.
12 + 12 = 24.
Eureka Math Grade 5 Module 2 Lesson 3 Answer Key (14)

Answer:
The sum of 3 fifteens and 4 twos = 53.

Explanation:
In the above-given question,
given that,
The sum of 3 fifteens and 4 twos
45 + 8.
53.
Eureka Math Grade 5 Module 2 Lesson 3 Answer Key (15)

Answer:
The difference between 9 thirty-sevens and 8 thirty-sevens = 37.

Explanation:
In the above-given question,
given that,
The difference between 9 thirty-sevens and 8 thirty-sevens
9 x 37 – 8 x 37.
333 – 296.
37.

Answer:

Triple the sum of 45 and 55 = 300.

Explanation:
In the above-given question,
given that,
Triple the sum of 45 and 55
45 + 55 = 100.
100 + 100 + 100 = 300.

Question 2.
Write the numerical expressions in words. Then, solve.

Expression

Words

The Value of the Expression

a. 10 × (2.5 + 13.5)one hundred and sixty10 x (16) = 160
b. (98 – 78) × 11two hundred and twenty(20) x 11 = 220
c. (71 + 29) × 26two thousand six hundred(100) x 26 = 2600
d. (50 × 2) + (15 × 2)one hundred and thirty(100) + 30 = 130

Answer:
160.

Explanation:
In the above-given question,
given that,
10 x ( 2.5 + 13.5).
10 x (16).
160.

Answer:
220.

Explanation:
In the above-given question,
given that,
11 x ( 98 – 78).
11 x (20).
220.

Answer:
2600.

Explanation:
In the above-given question,
given that,
26 x ( 71 + 29).
26 x (30).
2600.

Answer:
3000.

Explanation:
In the above-given question,
given that,
(50 x 2) + ( 15 + 2).
100 x (30).
3000.

Question 3.
Compare the two expressions using > , < , or = . In the space beneath each pair of expressions, explain how you can compare without calculating. Draw a model if it helps you.
Eureka Math Grade 5 Module 2 Lesson 3 Answer Key (16)

Answer:
3906 > 1438.

Explanation:
In the above-given question,
given that,
93 x ( 40 + 2).
93 x (42).
3906.
(40 + 2) x 36
42 x 36.
1438.
3906 > 1438.

Answer:
1525 > 1475.

Explanation:
In the above-given question,
given that,
61 x ( 25).
1525.
60 twenty fives minus one twenty-five.
60 x 25 – 25.
1500 – 25.
1475.
1525 > 1475.

Question 4.
Larry claims that (14 + 12) × (8 + 12) and (14 × 12) + (8 × 12) are equivalent because they have the same digits and the same operations.
a. Is Larry correct? Explain your thinking.

Answer:
Yes, Larry was not correct.

Explanation:
In the above-given question,
given that,
Larry claims that (14 + 12) x (8 + 12) and (14 x 12) + (8 x 12).
42 + 12 = 26.
8 + 12 = 20.
26 x 20 = 520.
(14 x 12) + (8 x 12).
168 + 96.
264.
520 is not equal to 264.

b. Which expression is greater? How much greater?

Answer:
(14 + 12) x (8 + 12) is greater.
256 is greater.

Explanation:
In the above-given question,
given that,
42 + 12 = 26.
8 + 12 = 20.
26 x 20 = 520.
(14 x 12) + (8 x 12).
168 + 96.
264.
520 is not equal to 264.

Eureka Math Grade 5 Module 2 Lesson 3 Answer Key (2024)
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